2x^2+x-5=(x+3)

Solution for 2x^2+x-5=(x+3) equation:

Simplifying
2x2 + x + -5 = (x + 3)

Reorder the terms:
-5 + x + 2x2 = (x + 3)

Reorder the terms:
-5 + x + 2x2 = (3 + x)

Remove parenthesis around (3 + x)
-5 + x + 2x2 = 3 + x

Add '-1x' to each side of the equation.
-5 + x + -1x + 2x2 = 3 + x + -1x

Combine like terms: x + -1x = 0
-5 + 0 + 2x2 = 3 + x + -1x
-5 + 2x2 = 3 + x + -1x

Combine like terms: x + -1x = 0
-5 + 2x2 = 3 + 0
-5 + 2x2 = 3

Solving
-5 + 2x2 = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 2x2 = 3 + 5

Combine like terms: -5 + 5 = 0
0 + 2x2 = 3 + 5
2x2 = 3 + 5

Combine like terms: 3 + 5 = 8
2x2 = 8

Divide each side by '2'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}